TS EAMCET · Physics · Rotational Motion

A planet is moving in a circular orbit. It completes $2$ revolutions in $360 days$ . What is its angular frequency?

A $1.5 \times 10^{- 2} rad {day}^{- 1}$
B $2.5 \times 10^{- 2} rad {day}^{- 1}$
C $3.5 \times 10^{- 2} rad {day}^{- 1}$
D $4.5 \times 10^{- 2} rad {day}^{- 1}$

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Answer & Solution

Correct Answer

(C) $3.5 \times 10^{- 2} rad {day}^{- 1}$

Step-by-step Solution

Detailed explanation

Given: The planet completes 2 revolutions in 360 days. One rotation of the planet moves 2π radians angle. Thus, angular frequency ω=θt, where θ represents the angle moved by the object and t represents the time taken by the object to travel through…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A planet is moving in a circular orbit. It completes 2 revolutions in 360 days. What is its angular frequency?

Step-by-step Solution

A planet is moving in a circular orbit. It completes $2$ revolutions in $360 days$ . What is its angular frequency?