TS EAMCET · Physics · Mechanical Properties of Fluids
A soap bubble of initial radius \(R\) is to be blown up. The surface tension of the soap film is \(\mathrm{T}\). The surface energy needed to double the diameter of the bubble is
- A \(12 \pi R^2 T\)
- B \(4 \pi \mathrm{R}^2 \mathrm{~T}\)
- C \(16 \pi R^2 T\)
- D \(24 \pi \mathrm{R}^2 \mathrm{~T}\)
Answer & Solution
Correct Answer
(D) \(24 \pi \mathrm{R}^2 \mathrm{~T}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \Delta \mathrm{U}=\mathrm{U}_f-\mathrm{U}_{\mathrm{i}} \\ & =\left[\mathrm{T}\left[4 \pi(2 \mathrm{R})^2\right]-\mathrm{T}\left[4 \pi \mathrm{R}^2\right]\right] \times 2 \\ & =32 \pi \mathrm{R}^2 \mathrm{~T}-8 \pi \mathrm{R}^2 \mathrm{~T}=24 \pi \mathrm{R}^2…
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