TS EAMCET · Physics · Oscillations
A body starting at from origin and oscillates simple harmonically with a period of . After what time will its kinetic energy be of its total energy
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
As we know, KE=12mv2=12mω2A2-x2 and TE=12mω2A2 As per question, KE=75100TE⇒12mω2A2-x2=12mω2A2⇒x=±A2 From mean position, time taken to reach half of the amplitude will be, T12=412=13 s
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