TS EAMCET · Physics · Motion In Two Dimensions
A projectile is given an initial velocity of \(\hat{i}+2 \hat{j} \mathrm{~ms}^{-1}\). The cartesian equation of its path is ( \(x\) and \(y\) are in metres and \(\mathrm{g}=10 \mathrm{~ms}^{-1}\) )
- A \(y=x-5 x^2\)
- B \(y=2 x-5 x^2\)
- C \(y=2 x-15 x^2\)
- D \(y=2 x-25 x^2\)
Answer & Solution
Correct Answer
(B) \(y=2 x-5 x^2\)
Step-by-step Solution
Detailed explanation
Cartesian equation path of projectile is given by \(y=x \tan \theta-\frac{g x^2}{2 u^2 \cos ^2 \theta}\) Given velocity \(u=\hat{i}+2 \hat{j} \mathrm{~m} / \mathrm{s}\)…
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