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TS EAMCET · Physics · Semiconductors

In a p-n junction, an electric field of 5×105 V m exists in the depletion region. The minimum kinetic energy of a conduction electron, in order to diffuse from n-side to the p-side, is found to be 3.2×10-20 J. The width of the depletion region is,

  1. A 2×10-4 cm
  2. B 8×10-5 cm
  3. C 5×10-6 cm
  4. D 4×10-5 cm
Verified Solution

Answer & Solution

Correct Answer

(D) 4×10-5 cm

Step-by-step Solution

Detailed explanation

The kinetic energy in terms of electric potential, K.E.=eV, it means the value of electric potential, V=K.E.e=3.2×10-201.6×10-19, now the relation between electric field strength and electric potential in terms of the width of the depletion region,…
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