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TS EAMCET · Physics · Motion In One Dimension

The relation between time \(t\) and distance \(x\) of a particle is \(t=a x^2+b x\), where \(a\) and \(\mathrm{b}\) are constants.
If \(\mathrm{v}\) is the velocity of the particle, then its acceleration is

  1. A \(-2abv^2\)
  2. B \(2bv^3\)
  3. C \(-2av^3\)
  4. D \(2av^2\)
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Answer & Solution

Correct Answer

(C) \(-2av^3\)

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