TS EAMCET · Physics · Electromagnetic Induction
The radius of a coil of N turns is R. If the plane of the coil is placed parallel to a uniform magnetic field B, then the flux linked with the coil is
- A \(\pi \mathrm{BNR}^2\)
- B \(2 \pi \mathrm{BNR}^2\)
- C \(\frac{\pi \mathrm{BNR}^2}{2}\)
- D Zero
Answer & Solution
Correct Answer
(D) Zero
Step-by-step Solution
Detailed explanation
\(\Phi = NBA \cos \theta\) \(\theta = 90^\circ\) (angle between area vector and magnetic field) \(\Phi = NBA \cos 90^\circ = 0\)
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