TS EAMCET · Physics · Thermal Properties of Matter
An auditorium has volume of \(10^5 \mathrm{~m}^3\) and surface area of absorption \(2 \times 10^4 \mathrm{~m}^2\). Its average absorption coefficient is 0.2 . The reverberation time of the auditorium in seconds is
- A \(6.5\)
- B \(5.5\)
- C \(4.25\)
- D \(3.25\)
Answer & Solution
Correct Answer
(C) \(4.25\)
Step-by-step Solution
Detailed explanation
Reverberation time \(T=\frac{0.017 v}{a s}\) where, \(a=\) average absorption coefficient \[ \begin{aligned} & =0.2 \\ T & =\frac{0.17 \times 10^5}{0.2 \times 2 \times 10^4}=4.25 \mathrm{sec} \end{aligned} \]
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