TS EAMCET · Physics · Mechanical Properties of Solids
If a brass sphere of radius 36 cm is submerged in a lake at a depth where the pressure is \(10^7 \mathrm{~Pa}\), then the change in the radius of the sphere is \((\) Bulk modulus of brass \(=60 \mathrm{GPa})\)
- A \(4 \times 10^{-2} \mathrm{~cm}\)
- B \(2 \times 10^{-3} \mathrm{~cm}\)
- C \(4 \times 10^{-3} \mathrm{~cm}\)
- D \(2 \times 10^{-2} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(2 \times 10^{-3} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\( \Delta V / V = 3 \Delta R / R \) \( B = -P / (\Delta V / V) \) \( B = -P / (3 \Delta R / R) \) \( \Delta R = -PR / (3B) \) \( |\Delta R| = (10^7 \mathrm{~Pa} \cdot 0.36 \mathrm{~m}) / (3 \cdot 60 \times 10^9 \mathrm{~Pa}) \)…
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