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TS EAMCET · Physics · Oscillations

A ball of mass 100 g is dropped at time t=0. A second ball of mass 200 g is dropped from the same point at t=0.2 s. The distance between the center of mass of two balls and the release point at t=0.4 s is: (Assume g=10 m s-2)

  1. A 0.4 m
  2. B 0.5 m
  3. C 0.6 m
  4. D 0.8 m
Verified Solution

Answer & Solution

Correct Answer

(A) 0.4 m

Step-by-step Solution

Detailed explanation

Given: Masses of the balls m1 and m2 are 100 g and 200 g. Applying the equation of motion s=ut+12gt2 for two cases. As the bast is at rest initially, u=0 thus distance travelled by the ball will be s=12gt2 Now, for the first ball s1=12gt12 and for the second ball…
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