TS EAMCET · Physics · Electromagnetic Waves
If the electric field of a plane electromagnetic wave is \(\mathrm{E}_z=60 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\), then the magnetic field of the wave is
- A \(\mathrm{B}_y=2 \times 10^{-7} \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}\)
- B \(\mathrm{B}_z=2 \times 10^{-7} \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}\)
- C \(\mathrm{B}_x=180 \times 10^8 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}\)
- D \(\mathrm{B}_y=180 \times 10^8 \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{B}_y=2 \times 10^{-7} \sin \left(0.5 \times 10^3 x+1.5 \times 10^{11} \mathrm{t}\right) \mathrm{T}\)
Step-by-step Solution
Detailed explanation
\(E_0 = 60 \mathrm{Vm}^{-1}\) \(B_0 = E_0/c = 60 / (3 \times 10^8) = 2 \times 10^{-7} \mathrm{T}\) Wave propagates in \(-x\) direction. Given \(\vec{E}\) is in \(z\) direction. For \(\vec{E} \times \vec{B}\) to be in \(-x\) direction, \(\vec{B}\) must be in \(y\) direction.…
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