TS EAMCET · Physics · Rotational Motion
A thin wire of length \(l\) having density \(\rho\) is bent into a circular loop with \(C\) as its centre, as shown in figure. The moment of inertia of the loop about the line \(A B\) is
- A \(\frac{5 \rho l^3}{16 \pi^2}\)
- B \(\frac{\rho l^3}{16 \pi^2}\)
- C \(\frac{\rho l^3}{8 \pi^2}\)
- D \(\frac{3 \rho l^3}{8 \pi^2}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 \rho l^3}{8 \pi^2}\)
Step-by-step Solution
Detailed explanation
The moment of inertia \[ I=\frac{3}{2} m R^2 \] \(\left[\because\right.\) Linear density \(\rho=\frac{m}{l}\)…
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