TS EAMCET · Physics · Motion In One Dimension
A person wearing a parachute jumps off a plane from a height of 2 km from the ground and falls freely for 20 m before his parachute opens. After his parachute opens if he continues to move uniformly with the velocity attained due to his freefall, the total time taken by the person to reach the ground is
(Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A 99 s
- B 100 s
- C 101 s
- D 102 s
Answer & Solution
Correct Answer
(C) 101 s
Step-by-step Solution
Detailed explanation
\(v = \sqrt{u^2 + 2as}\) \(v = \sqrt{0^2 + 2 \times 10 \times 20} = 20 \text{ ms}^{-1}\) \(t_1 = \frac{v-u}{a}\) \(t_1 = \frac{20-0}{10} = 2 \text{ s}\) \(s_2 = 2000 \text{ m} - 20 \text{ m} = 1980 \text{ m}\) \(t_2 = \frac{s_2}{v}\) \(t_2 = \frac{1980}{20} = 99 \text{ s}\)…
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