TS EAMCET · Physics · Gravitation
An artificial satellite of mass \(m\) revolves around the earth at a height \(h\) with a speed \(v\). How much power (energy per second) will it require to keep itself moving with constant speed in the orbit of radius \(r\) ?
- A \(\frac{m v^3}{r}\)
- B \(\frac{1}{2} m v^2\)
- C \(\frac{6 m M_e}{\left(R_e+b\right)}\)
- D 0
Answer & Solution
Correct Answer
(D) 0
Step-by-step Solution
Detailed explanation
Speed of satellite is constant, so by workenergy theorem, \[ \begin{aligned} & W=K_f-K_{\dot{i}} \\ & W=\frac{1}{2} m v^2-\frac{1}{2} m v^2 \\ & W=0 \end{aligned} \] As, work on satellite is zero, so power required will also be zero, i.e. \(P=\frac{W}{t}=0\)
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