TS EAMCET · Physics · Work Power Energy
A body of mass 500 g is falling from rest from a height of 3.2 m from the ground. If the body reaches the ground with a velocity of \(6 \mathrm{~ms}^{-1}\), then the energy lost by the body due to air resistance is
\(\left(\right.\) Acceleration due to gravity \(\left.=10 \mathrm{~ms}^{-2}\right)\)
- A 14 J
- B 7 J
- C 21 J
- D 28 J
Answer & Solution
Correct Answer
(B) 7 J
Step-by-step Solution
Detailed explanation
\(E_{lost} = mgh - \frac{1}{2}mv^2\) \(E_{lost} = (0.5 \mathrm{~kg})(10 \mathrm{~ms}^{-2})(3.2 \mathrm{~m}) - \frac{1}{2}(0.5 \mathrm{~kg})(6 \mathrm{~ms}^{-1})^2\) \(E_{lost} = 16 \mathrm{~J} - 9 \mathrm{~J}\) \(E_{lost} = 7 \mathrm{~J}\)
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