TS EAMCET · Physics · Center of Mass Momentum and Collision
From a uniform circular disc of radius \(2 \mathrm{~cm}\) (its centre of mass is at \(O\) ) a circular portion of radius \(1 \mathrm{~cm}\) is removed such that the shift in centre of mass is maximum. The disc is now rotated by an angle \(\theta\) about an axis perpendicular to its plane and passing through \(O\). If the magnitude of displacement of new centre of mass is \(\frac{1}{\sqrt{3}} \mathrm{~cm}\), then the \(\theta\) is
- A \(30^{\circ}\)
- B \(45^{\circ}\)
- C \(60^{\circ}\)
- D \(120^{\circ}\)
Answer & Solution
Correct Answer
(D) \(120^{\circ}\)
Step-by-step Solution
Detailed explanation
The situation given can be shown as, Here, \(R\) be the radius of circular disc \(=2 \mathrm{~cm}\) The radius of removed portion, \(r=1 \mathrm{~cm}\) Area of whole disc, \(A_1=\pi R^2=4 \pi \mathrm{cm}^2\) Area of removed portion, \(A_2=\pi r^2=\pi \mathrm{cm}^2\) As,…
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