TS EAMCET · Physics · Mechanical Properties of Solids
The ratio of the areas of cross sections of three wires in 1:2:3 and the ratio of the Young's modulii of their materials is \(3: 2: 1\). If the three wires are of same length and same stretching force is applied to the three wires, then the ratio of the elongations of the three wires is
- A \(4: 3: 4\)
- B \(1: 1: 1\)
- C \(9: 4: 1\)
- D \(3: 4: 3\)
Answer & Solution
Correct Answer
(A) \(4: 3: 4\)
Step-by-step Solution
Detailed explanation
From Hookes law, \(\mathrm{Y}=\frac{\frac{\mathrm{F}}{\mathrm{A}}}{\frac{\Delta \mathrm{l}}{\mathrm{l}_0}}\) or \(\frac{\mathrm{Fl}_0}{\mathrm{AY}}=\Delta \mathrm{l}\) \(\mathrm{F}\) and \(\mathrm{l}_0\) same for three wires \(\therefore \Delta 1 \propto \frac{1}{\mathrm{AY}}\)…
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