TS EAMCET · Physics · Gravitation
If a planet of mass \(6.4 \times 10^{23} \mathrm{~kg}\) can be compressed into a sphere such that the escape velocity from its surface is \(8 \times 10^4 \mathrm{~m} / \mathrm{s}\), then what showld be the radius of the sphere? (Gravitational constant, \(G=6.6 \times 10^{11} \mathrm{Nm}^2 \mathrm{~kg}^2\) )
- A \(40.4 \mathrm{~km}\)
- B \(13.2 \mathrm{~km}\)
- C \(20.4 \mathrm{~km}\)
- D \(6.8 \mathrm{~km}\)
Answer & Solution
Correct Answer
(B) \(13.2 \mathrm{~km}\)
Step-by-step Solution
Detailed explanation
As, we know, the escape velocity of a planet is given as or \[ \begin{aligned} & v_e=\sqrt{\frac{2 G M}{R}} \\ & v_e^2=\frac{2 G M}{R} \end{aligned} \] Radius of sphere \(=\frac{2 G M}{v_e^2}\) where,…
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