TS EAMCET · Physics · Mathematics in Physics
Sum of magnitudes of two forces acting at a point is \(16 \mathrm{~N}\). If their resultant is normal to smaller force, and has a magnitude \(8 \mathrm{~N}\), then forces are
- A \(6 \mathrm{~N}, 10 \mathrm{~N}\)
- B \(8 \mathrm{~N}, 8 \mathrm{~N}\)
- C \(4 \mathrm{~N}, 12 \mathrm{~N}\)
- D \(2 \mathrm{~N}, 14 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(6 \mathrm{~N}, 10 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\((16-x)^2=8^2+x^2\) \(\begin{aligned} 256+x^2-32 x & =64+x^2 \\ 32 x & =192 \\ x & =\frac{192}{32}=6\end{aligned}\) \(\therefore\) Forces \(6 \mathrm{~N}, 10 \mathrm{~N}\)
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