TS EAMCET · Physics · Motion In Two Dimensions
From a height of ' \(h\) ' above the ground, a ball is projected up at an angle \(30^{\circ}\) with the horizontal. If the ball strikes the ground with a speed of 1.25 times its initial speed of \(40 \mathrm{~ms}^{-1}\), the value of ' \(h\) ' is (acceleration due to gravity \(=\) \(10 \mathrm{~ms}^{-2}\) )
- A 75 m
- B 60 m
- C 30 m
- D 45 m
Answer & Solution
Correct Answer
(D) 45 m
Step-by-step Solution
Detailed explanation
x\(\mathrm{u}=40 \mathrm{~ms}^{-1}, \mathrm{v}=1.25 \times 40=50 \mathrm{~ms}^{-1}\)…
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