TS EAMCET · Physics · Work Power Energy
The displacement 's' of a body of mass \(3 \mathrm{~kg}\) under the action of a force is given by \(s=\frac{t^3}{3}\), where ' \(s\) ' is in metres and ' \(t\) ' is in seconds. The work done by the force in the first two seconds is
- A \(32J\)
- B \(3.8J\)
- C \(5.2J\)
- D \(24J\)
Answer & Solution
Correct Answer
(D) \(24J\)
Step-by-step Solution
Detailed explanation
Masses of body, \(\mathrm{m}=3 \mathrm{~kg}\) The action of force is given, \(s=\frac{t^3}{3}\) Velocity, \(v=\frac{\mathrm{ds}}{\mathrm{dt}}=\mathrm{t}^2\) acceleration, \(\mathrm{a}=\frac{\mathrm{d} v}{\mathrm{dt}}=2 \mathrm{t}\)…
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