TS EAMCET · Physics · Current Electricity
The sensitivity of a galvanometer that measures current is decreased by \(\frac{1}{40}\) times by using shunt resistance of \(10 \Omega\). Then, the value of the resistance of the galvanometer is
- A \(400 \Omega\)
- B \(410 \Omega\)
- C \(30 \Omega\)
- D \(390 \Omega\)
Answer & Solution
Correct Answer
(D) \(390 \Omega\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} i_g & =\frac{S}{S+G} i \\ \frac{1}{40} & =\frac{10}{10+x} \\ \Rightarrow \quad 10+x & =400 \\ \Rightarrow \quad x & =390 \Omega\end{aligned}\)
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