TS EAMCET · Physics · Center of Mass Momentum and Collision
A block of mass \(100 \mathrm{~g}\) is suspended vertically from a massless spring system of spring constant, \(k=1 \mathrm{~N} / \mathrm{m}\) each. The block is hit from above to impart an impulse of 2 Ns. Calculate the maximum displacement from the Equilibrium position of the block. (Take, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(2 \mathrm{~m}\)
- B \(4 m\)
- C \(5 \mathrm{~m}\)
- D \(9 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(4 m\)
Step-by-step Solution
Detailed explanation
Given, mass \(m=100 \mathrm{~g}=0.1 \mathrm{~kg}\), spring constant, \(k=1 \mathrm{~N} / \mathrm{m}\) and impulse, \(I=2 \mathrm{~N} \mathrm{~s}\) The given system has parallel connection of the springs. So, time period,…
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