TS EAMCET · Physics · Center of Mass Momentum and Collision
A rifle of \(20 \mathrm{~kg}\) mass can fire 4 bullets per second. The mass of each bullet is \(35 \times 10^{-3} \mathrm{~kg}\) and its final velocity is \(400 \mathrm{~ms}^{-1}\). Then what force must be applied on the rifle so that it does not move backwards while firing the bullets ?
- A \(80 \mathrm{~N}\)
- B \(28 \mathrm{~N}\)
- C \(-112 \mathrm{~N}\)
- D \(-56 \mathrm{~N}\)
Answer & Solution
Correct Answer
(D) \(-56 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
From conservation of momentum \(\begin{aligned} & M V+(4 m v)=0 \\ \Rightarrow \quad V & =-\frac{4 m v}{M}=-\frac{4 \times 35 \times 10^{-3} \times 400}{20} \\ = & -2.8 \mathrm{~ms}^{-1}\end{aligned}\) Force applied on the rifle,…
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