TS EAMCET · Physics · Units and Dimensions
Force \(F\) is given by the equation \(F=\frac{X}{\text { Linear density }}\). Then dimensions of \(X\) are
- A \(\left[\mathrm{M}^2 \mathrm{~L}^0 \mathrm{~T}^{-2}\right]\)
- B \(\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]\)
- C \(\left[\mathrm{L}^2 \mathrm{~T}^{-2}\right]\)
- D \(\left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{M}^2 \mathrm{~L}^0 \mathrm{~T}^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(F=\frac{X}{\text { Linear density }}\) Dimension of \(F=\left[\mathrm{MLT}^{-2}\right]\) Dimension of linear density \(=\left[\mathrm{ML}^{-1}\right]\)…
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