TS EAMCET · Physics · Mechanical Properties of Solids
Water in a river \(20 \mathrm{~m}\) deep is flowing at a speed of \(10 \mathrm{~ms}^{-1}\). The shearing stress between the horizontal layers of water in the river in \(\mathrm{Nm}^{-2}\) is (Coefficient of viscosity of water \(=10^{-3} \mathrm{ \ SI}\) units)
- A \(1 \times 10^{-2}\)
- B \(0.5 \times 10^{-2}\)
- C \(1 \times 10^{-3}\)
- D \(0.5 \times 10^{-3}\)
Answer & Solution
Correct Answer
(D) \(0.5 \times 10^{-3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \text { Shearing stress } & =\eta\left(\frac{d v}{d x}\right) \\ & =10^{-3}\left(\frac{10}{20}\right) \\ & =0.5 \times 10^{-3} \mathrm{Nm}^{-2}\end{aligned}\)
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