TS EAMCET · Physics · Oscillations
A simple pendulum of length \(1 \mathrm{~m}\) and having a bob of mass \(100 \mathrm{~g}\) is suspended in a car, moving on a circular track of radius \(100 \mathrm{~m}\) with uniform speed \(10 \mathrm{~m} / \mathrm{s}\). If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by \(\mathrm{T}=2 \pi / \alpha^{1 / 4}\). The value of \(\alpha\) is [Take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) ] [Take g = 10 m/s2]
- A 11
- B 110
- C 101
- D 1100
Answer & Solution
Correct Answer
(C) 101
Step-by-step Solution
Detailed explanation
The bob of the simple pendulum will experience the acceleration due to gravity and the centripetal acceleration provided by the circular motion of the car. Acceleration due to gravity \(=\mathrm{g}\) Centripetal acceleration \(=\mathrm{v}^2 / \mathrm{R}\) Effective acceleration…
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