TS EAMCET · Physics · Electrostatics
\(6 \mu C\) charge is placed at the centre of a cube. What will be the electric flux at each face of the tube? \[ \left[\text { Take } \frac{1}{4 \pi \epsilon_o}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right] \]
- A \(9 \pi \times 10^2 \mathrm{Nm}^2 / \mathrm{C}\)
- B \(36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\)
- C \(3.6 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\)
- D \(4 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \left.\phi_{\text {net }}\right|_{\text {side }}=\frac{q_{\text {net }}}{6 \epsilon_0} \\ & =\frac{6 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}} \\ & =112994.35 \\ & \simeq 36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\end{aligned}\)
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