TS EAMCET · Physics · Kinetic Theory of Gases
For a given mass of a gas at constant temperature, the volume and the pressure are \(\mathrm{V}\) and \(\mathrm{P}\) respectively. Then the slope of the graph drawn between \(\log _e V\) on \(\mathrm{X}\)-axis and \(\log _{\mathrm{e}} \mathrm{P}\) on \(\mathrm{Y}\)-axis is
- A \(1\)
- B \(-1\)
- C zero
- D Infinity
Answer & Solution
Correct Answer
(B) \(-1\)
Step-by-step Solution
Detailed explanation
Using ideal gas equation, \[ \mathrm{PV}=\mathrm{nRT} \] Taking log both sides, \[ \begin{aligned} & \log (\mathrm{P})+\log (\mathrm{V})=\log (\mathrm{nRT}) \\ & \log (\mathrm{P})=-\log (\mathrm{V})+\log (\mathrm{nRT}) \end{aligned} \] Equation of line is given as, \[ y=m x+c \]…
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