TS EAMCET · Physics · Mechanical Properties of Fluids
Drops of liquid of density \(d\) are floating half immersed in a liquid of density \(\rho\). If the surface tension of the liquid is \(T\), then the radius of the drop is
- A \(\sqrt{\frac{3 T}{g(3 d-\rho)}}\)
- B \(\sqrt{\frac{6 T}{g(2 d-\rho)}}\)
- C \(\sqrt{\frac{3 T}{g(2 d-p)}}\)
- D \(\sqrt{\frac{3 T}{g(4 d-3 p)}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{\frac{3 T}{g(2 d-p)}}\)
Step-by-step Solution
Detailed explanation
According to the question, \(\frac{4}{3} \pi r^3 d g=\frac{2}{3} \pi r^3 \rho g+T \times 2 \pi r\) or \(r=\sqrt{\frac{3 T}{g(2 d-\rho)}}\)
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