TS EAMCET · Physics · Mechanical Properties of Solids
A wire of length \(40 \mathrm{~cm}\) is stretched by \(0.1 \mathrm{~cm}\). The strain on the wire is
- A \(25 \times 10^{-4}\)
- B \(40 \times 10^{-4}\)
- C \(10 \times 10^{-4}\)
- D \(12.5 \times 10^{-4}\)
Answer & Solution
Correct Answer
(A) \(25 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {Strain }=\frac{\Delta \ell}{\ell} \\ & =\frac{0.1}{40}=25 \times 10^{-4} \mathrm{~cm}\end{aligned}\)
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