TS EAMCET · Physics · Magnetic Effects of Current
The ratio of the magnetic field inside a solenoid at an axial point well inside and at an axial end point is
- A 2
- B \(\frac{1}{2}\)
- C 1
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
The magnetic field at some internal point on the axis of a solenoid is given by \(B=\frac{\mu_0 n I}{2}\left(\cos \theta_1-\cos \theta_2\right)\) Magnetic field at the centre of a long solenoid is given by setting \(\theta_1=0^{\circ}\) and \(\theta_2=\pi\).…
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