TS EAMCET · Physics · Semiconductors

What is the binding energy of ${}_{14}^{29}S i$ whose atomic mass is $28.976495 u$ Mass of proton $= 1.007276 u$ Mass of neutron $= 1.008664 u$ (Neglect the electron mass) (Assume $1 u = 931.5 MeV$ )

A $237.86 MeV$
B $421.72 MeV$
C $387.21 MeV$
D $116.35 MeV$

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Answer & Solution

Correct Answer

(A) $237.86 MeV$

Step-by-step Solution

Detailed explanation

Given: Atomic mass of S1429i is 28.976495 u. Mass of proton =1.007276 u Mass of neutron =1.008664 u The binding energy for S1429i can be calculated from the mass defect. B.E=∆mc2, where ∆m is the change in mass and c is the speed of light. In S1429i…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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What is the binding energy of S1429i whose atomic mass is 28.976495 u Mass of proton =1.007276 u Mass of neutron =1.008664 u (Neglect the electron mass) (Assume 1 u=931.5 MeV)

Step-by-step Solution

What is the binding energy of ${}_{14}^{29}S i$ whose atomic mass is $28.976495 u$ Mass of proton $= 1.007276 u$ Mass of neutron $= 1.008664 u$ (Neglect the electron mass) (Assume $1 u = 931.5 MeV$ )