TS EAMCET · Physics · Mechanical Properties of Fluids
Consider an air bubble of radius \(2 \mathrm{~mm}\) in a liquid at a depth of \(5 \mathrm{~cm}\) below the free surface. The density of the liquid is \(1000 \mathrm{lg} / \mathrm{m}^3\) and the surface tension is \(0.1 \mathrm{~N} / \mathrm{m}\). Then, find the pressure inside the air bubble is greater than the pressure at the free surface of the liquid. (Talse, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(500 \mathrm{~Pa}\)
- B \(600 \mathrm{~Pa}\)
- C \(700 \mathrm{~Pa}\)
- D \(800 \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(B) \(600 \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
Gauge pressure due to liquid at a depth of \(5 \mathrm{~cm}\) \[ p=\rho g h \] Density, \(\rho=1000 \mathrm{~kg} / \mathrm{m}^3, h=5 \mathrm{~cm}=0.05 \mathrm{~m}\),…
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