TS EAMCET · Physics · Mathematics in Physics
Sum of magnitude of two forces is \(25 \mathrm{~N}\). The resultant of these forces is normal to the smaller force and has a magnitude of \(10 \mathrm{~N}\). Then the two forces are
- A \(14.5 \mathrm{~N}, 10.5 \mathrm{~N}\)
- B \(16 \mathrm{~N}, 9 \mathrm{~N}\)
- C \(13 \mathrm{~N}, 12 \mathrm{~N}\)
- D \(20 \mathrm{~N}, 5 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(14.5 \mathrm{~N}, 10.5 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Sum of two forces \(F_1+F_2=25\) Resultant of these forces \((10)^2=F_1^2+F_2^2+2 F_1 F_2 \cos \theta\) Since, resultant is normal to the smaller force \(\therefore \quad F_1+F_2 \cos \theta=0\) From Eqs. (i), (ii) and (iii), we get…
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