TS EAMCET · Physics · Motion In Two Dimensions
A body of mass \(m\) thrown up vertically with velocity \(v_1\) reaches a maximum height \(h_1\) in \(t_1\) seconds. Another body of mass \(2 \mathrm{~m}\) is projected with a velocity \(v_2\) at an angle \(\theta\). The second body reaches a maximum height \(h_2\) in time \(t_2\) seconds. If \(t_1=2 t_2\), then ratio \(\left(\frac{h_1}{h_2}\right)\) is
- A \(1: 2\)
- B \(4: 1\)
- C \(1: 1\)
- D \(3: 2\)
Answer & Solution
Correct Answer
(B) \(4: 1\)
Step-by-step Solution
Detailed explanation
Maximum vertical height attained by body thrown with velocity \(v_1\) \[ h_1=\frac{v_1^2}{2 g} \] Another body of mass \(2 \mathrm{~m}\) is projected with a velocity \(v_2\) at an angle \(\theta\). \(\therefore\) Height attained…
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