TS EAMCET · Physics · Laws of Motion
A block of mass \(5 \mathrm{~kg}\) is pulled by a force \(F\) as shown in the figure. If the coefficient of friction is 0.1 , then the force needed to accelerate the block to \(3 \mathrm{~m} / \mathrm{s}^2\) to the right is close to
- A \(12 \mathrm{~N}\)
- B \(22 \mathrm{~N}\)
- C \(32 \mathrm{~N}\)
- D \(42 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(22 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Component of force accelerating the block is \(f \cos \theta\). Net force on block, \(F_{\text {net }}=F \cos \theta-\mu N\) \[ \begin{aligned} & =F \cos 30^{\circ}-0.1 \times 5 \times 9.8 \\ & =\frac{\sqrt{3} F}{2}-49 \end{aligned} \] From, \(F_{\text {net }}=m a\), we have,…
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