TS EAMCET · Physics · Rotational Motion
Consider a thin metal strip of mass \(1 \mathrm{~kg}\) and length \(5 \mathrm{~m}\). Calculate its moment of inertia about an axis perpendicular to strip and located at \(100 \mathrm{~cm}\) on strip from one its end. (Assume the breadth as the strip is negligible)
- A \(4.33 \mathrm{~kg}-\mathrm{m}^2\)
- B \(4.85 \mathrm{~kg}-\mathrm{m}^2\)
- C \(4.11 \mathrm{~kg}-\mathrm{m}^2\)
- D \(4.66 \mathrm{~kg}-\mathrm{m}^2\)
Answer & Solution
Correct Answer
(A) \(4.33 \mathrm{~kg}-\mathrm{m}^2\)
Step-by-step Solution
Detailed explanation
The given situation is as shown below, Here, \(O\) is the point where centre of mass of whole strip exist. The point \(O^{\prime}\) is \(100 \mathrm{~cm}\) or \(1 \mathrm{~m}\) away from one end. So, its distance from centre of mass or from point \(O\) is \(1.5 \mathrm{~m}\).…
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