TS EAMCET · Physics · Wave Optics
In Young's double slit experiment, the \(10^{\text {th }}\) maximum of wavelength \(\lambda_1\) is at a distance of \(y_1\) from the central maximum. When the wavelength of the source is changed to \(\lambda_2, 5^{\text {th }}\) maximum is at a distance of \(y_2\) from its central maximum. The ratio \(\left(\frac{y_1}{y_2}\right)\) is
- A \(\frac{2 \lambda_1}{\lambda_2}\)
- B \(\frac{2 \lambda_2}{\lambda_1}\)
- C \(\frac{\lambda_1}{2 \lambda_2}\)
- D \(\frac{\lambda_2}{2 \lambda_1}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \lambda_2}{\lambda_1}\)
Step-by-step Solution
Detailed explanation
Position fringe from central maxima \(y_1=\frac{n \lambda_1 D}{d}\) Given, \(n=10\) \(y_1=\frac{10 \lambda_1 D}{d}\)...(i) \(y_2=\frac{5 \lambda_2 D}{d}\)...(ii) For second source \(\therefore \quad \frac{y_1}{y_2}=\frac{\frac{10 \lambda_1 D}{d}}{\frac{5 \lambda_2 D}{d}}\)…
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