TS EAMCET · Physics · Laws of Motion
A block of mass \(4 \mathrm{~kg}\) at rest on a rough inclined plane making an angle of \(\theta\) with the horizontal. The coefficient of static friction between the block and plane is 0.5 and the frictional force on the block is \(14.14 \mathrm{~N}\), find the value of \(\theta\) ?
- A \(30^{\circ}\)
- B \(45^{\circ}\)
- C \(60^{\circ}\)
- D \(15^{\circ}\)
Answer & Solution
Correct Answer
(B) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
Given, \(m=4 \mathrm{~kg}, \mu_s=0.5\) \(f r_k=14.14 \mathrm{~N}=10 \sqrt{2} \mathrm{~N}\) Normal reaction force, \(N=m g \cos \theta=4 \times 10 \times \cos \theta=40 \cos \theta\) and kinetic friction,…
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