TS EAMCET · Physics · Work Power Energy
A simple pendulwm of length \(L\) carries a bob of mass \(m\). When the bob is at its lowest position, it is given that the minimum horizontal speed necessary for it to move in a vertical circle about the point of suspension. When the string is horizontal, the net force on the bob is
- A \(\sqrt{10} m g\)
- B \(\sqrt{5} m g\)
- C \(4 \mathrm{mg}\)
- D \(1 \mathrm{mg}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{10} m g\)
Step-by-step Solution
Detailed explanation
According to the question, the bob is moving in a vertical circle, so the velocity at lowest point \(v=\sqrt{5 r g}\) Now, applying conservation of mechanical energy, we get \[ \frac{1}{2} m \times 5 r g=\frac{1}{2} m v^2+m g r \] or,…
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