TS EAMCET · Physics · Thermodynamics
Work done on heating one mole of monoatomic gas adiabatically through \(20^{\circ} \mathrm{C}\) is \(W\). Then, the work done on heating 6 moles of rigid diatomic gas through the same change in temperature
- A \(9 W\)
- B \(10 W\)
- C \(12 W\)
- D \(8 W\)
Answer & Solution
Correct Answer
(B) \(10 W\)
Step-by-step Solution
Detailed explanation
Work done in an adiabatic expansion is \(\Delta W=\frac{\mu R \Delta T}{\gamma-1}\) For 1 mole of monoatomic gas, \(\Delta T=20^{\circ} \mathrm{C}, \gamma=\frac{5}{3}\)…
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