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TS EAMCET · Physics · Motion In One Dimension

The displacement of a particle moving in a straight line is given by the expression \(x=A t^3+B t^2+C t+D\) in metres, where \(t\) is in seconds and \(A, B, C\) and \(D\) are constants. The ratio between the initial acceleration and initial velocity is

  1. A \(\frac{2 C}{B}\)
  2. B \(\frac{2 B}{C}\)
  3. C \(2 \mathrm{C}\)
  4. D \(\frac{C}{2 B}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2 B}{C}\)

Step-by-step Solution

Detailed explanation

Displacement of a particle moving in a straight line \((x)=A t^3+B t^2+C t+D\) \(\therefore\) Velocity,\(\quad v=\frac{d x}{d t}=3 A t^2+2 B t+C\) \[ v_{\text {initial }}=C \] and…