TS EAMCET · Physics · Center of Mass Momentum and Collision
An alphabet ' \(T\) ' made of two similar thin uniform metal plates of each length ' \(L\) ' and width ' \(a\) ' is placed on a horizontal surface as shown in the figure. If the alphabet is vertically inverted, the shift in the position of its centre of mass from the horizontal surface is
- A \(\frac{L-a}{2}\)
- B \(\frac{a-L}{2}\)
- C \(L-\frac{a}{2}\)
- D \(\frac{L}{2}-a\)
Answer & Solution
Correct Answer
(A) \(\frac{L-a}{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { (a) } A_1=L a, A_2=L a \\ & y_1=\frac{L}{2}, y_2=L+\frac{a}{2} \\ & \therefore y_{c m}=\frac{A_1 y_1+A_2 A_2}{A_1+A_2} \\ & =\frac{\frac{L}{2}+L+\frac{a}{2}}{2} \\ & =\left(\frac{3 L}{4}+\frac{a}{4}\right) \end{aligned}\) Centre of mass from top,…
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