TS EAMCET · Physics · Units and Dimensions
Dimensions of the quantity \(\frac{p}{\varepsilon_0 \mu_0}\), where \(p\) is the pressure, \(\varepsilon_0\) is electric permittivity of free space and \(\mu_0\) is permeability of free space, will be
- A \(\left[\mathrm{MLT}{ }^4\right]\)
- B \(\left[\mathrm{ML}^2 \mathrm{~T}^2\right]\)
- C \(\left[\mathrm{ML}^3 \mathrm{~T}^3\right]\)
- D \(\left[\mathrm{ML}^2 \mathrm{~T}^4\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{MLT}{ }^4\right]\)
Step-by-step Solution
Detailed explanation
Given, quantity \(=\frac{p}{\varepsilon_0 \mu_0}\), where, \(p=\) pressure, \(\varepsilon_0=\) permittivity of free space and \(\mu_0=\) permeability of free space. We know that, speed of light, \(c=\frac{1}{\sqrt{\varepsilon_0 \mu_0}}\) or \(c^2=\frac{1}{\varepsilon_0 \mu_0}\)…
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