TS EAMCET · Physics · Dual Nature of Matter
A photon of energy \(E\) ejects a photoelectron from a metal surface whose work function is \(W_0\). If this electron enters into a uniform magnetic field of induction \(B\) in a direction perpendicular to the field and describes a circular path of radius \(r\), then the radius \(r\) is given by, (in the usual notation)
- A \(\frac{\sqrt{2 m\left(E-W_0\right)}}{e B}\)
- B \(\sqrt{2 m\left(E-W_0\right) e B}\)
- C \(\frac{\sqrt{2 e\left(E-W_0\right)}}{m B}\)
- D \(\frac{\sqrt{2 m\left(E-W_0\right)}}{e B}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{2 m\left(E-W_0\right) e B}\)
Step-by-step Solution
Detailed explanation
From Einstein's equation \(\begin{gathered} E=W_0+\frac{1}{2} m v^2 \\ \sqrt{\frac{2\left(E-W_0\right)}{m}}=v \end{gathered}\) or A charged particle placed in uniform magnetic field experience a force \(F=\frac{m v^2}{r}\)…
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