TS EAMCET · Physics · Oscillations
With a standard rectangular bar magnet of length (l), breadth \((b ; b< < l)\) and magnetic moment \(M\), the time period of the magnet in a vibration magnetometer is \(4 \mathrm{~s}\). If the magnet is cut normal to its length into four equal pieces, the time period (in seconds) with one of the pieces is
- A 16
- B 2
- C 1
- D \(1 / 4\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
Time period of magnet in vibration magnetometer, \(T=2 \pi \sqrt{\frac{1}{M H}}\) where, \(I=\) moment of inertia of magnet \(M=\) magnetic moment \(H=\) horizontal component of earth's magnetic field…
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