TS EAMCET · Physics · Gravitation
The ratio of the time periods of a simple pendulum at heights \(2 R_E\) and \(3 R_E\) from the surface of the earth is
( \(R_E\) is radius of the earth)
- A \(1: 2\)
- B \(1: 3\)
- C \(3: 4\)
- D \(2: 3\)
Answer & Solution
Correct Answer
(C) \(3: 4\)
Step-by-step Solution
Detailed explanation
\( T \propto (R_E+h) \) \( \frac{T_1}{T_2} = \frac{R_E + 2R_E}{R_E + 3R_E} = \frac{3R_E}{4R_E} = \frac{3}{4} \)
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