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TS EAMCET · Physics · Electromagnetic Induction

A rod of length \(80 \mathrm{~cm}\) rotates about its mid point with a frequency of \(10 \mathrm{rev} / \mathrm{s}\). The potential difference (in volts) between two ends of the rod due to a magnetic field, \(B=0.5 \mathrm{~T}\) directed perpendicular to the rod is

  1. A \(\pi\)
  2. B \(1.6 \pi\)
  3. C \(2 \pi\)
  4. D \(0.8 \pi\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1.6 \pi\)

Step-by-step Solution

Detailed explanation

Given, frequency of revolution of the rod, \(f=10 \mathrm{rev} / \mathrm{s}\), length of rod, \(L=80 \mathrm{~cm}=0.8 \mathrm{~m}\) and magnetic field \(B=0.5 \mathrm{~T}\) Since, rod is rotated about its mid point, hence radius of circular revolution,…
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