TS EAMCET · Physics · Current Electricity
The current density in a circular wire is given by \(J(r)=\) \(\left(1 \times 10^5 \mathrm{~A} / \mathrm{m}^3\right) r\), where \(r\) is the radial distance and the wire's radius is \(2 \mathrm{~mm}\). If the potential applied across the wire is 70 \(\mathrm{V}\), then the energy consumed by the wire in 1000 seconds is
- A \(25 \mathrm{~kJ}\)
- B \(37 \pi \mathrm{kJ}\)
- C \(18 \pi \mathrm{kJ}\)
- D \(88 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(37 \pi \mathrm{kJ}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}=\int \mathrm{JdA}\)…
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